CARA'S TIPS
Technical Drawing · Lesson 2

Lines, angles, triangles, polygons, circles, inscribed and escribed figures

WAECNECO

What the syllabus asks

WAEC: WAEC/NECO Technical Drawing, Plane Geometry items 3 (division of lines in equal parts and proportion), 5 (angles: types and constructions), 6 (triangles, quadrilaterals, regular and irregular polygons), 7 (circles: parts, types, properties, constructions) and 9 (inscribed, circumscribed and escribed figures). (Not a JAMB UTME subject: Technical Drawing is absent from JAMB’s official IBASS…

NECO: WAEC/NECO Technical Drawing, Plane Geometry items 3 (division of lines in equal parts and proportion), 5 (angles: types and constructions), 6 (triangles, quadrilaterals, regular and irregular polygons), 7 (circles: parts, types, properties, constructions) and 9 (inscribed, circumscribed and escribed figures). (Not a JAMB UTME subject: Technical Drawing is absent from JAMB’s official IBASS…

What you will learn

Key points

Start here: Lines and the perpendicular bisector

Plane geometry is the construction of flat figures with compasses and a straight edge, using exact geometric reasoning rather than measuring with a protractor. WAEC Paper 2 and the plane-geometry part of Paper 1 depend heavily on it, and every later topic (tangency, loci, projection, development) uses these basic constructions. Draw all construction arcs lightly and leave them visible: they show the examiner your method.

Basic terms

Construction 1: bisect a line AB

Bisecting a line AB (perpendicular bisector)ABMPQRadius > half AB from A and B; PQ ⊥ AB through M, AM = MB
  1. Set the compasses to a radius greater than half of AB.
  2. With centre A, draw arcs above and below AB.
  3. With centre B and the same radius, draw arcs cutting the first two at P and Q.
  4. Join PQ. It cuts AB at M, the midpoint, and PQ is perpendicular to AB.

Why it works. P is the same distance from A and from B (both equal the radius), and so is Q. The set of points equidistant from A and B is the perpendicular bisector of AB; two points fix that line. Triangles APQ and BPQ are congruent (SSS), so PQ meets AB at right angles at its midpoint.

Construction 2: perpendicular from a point on a line

Given point C on a line: with centre C draw an arc cutting the line at D and E (CD = CE). Bisect DE as above; the bisector passes through C and is the required perpendicular.

Construction 3: perpendicular from a point off the line

Given point P above a line: with centre P draw an arc cutting the line at D and E. With centres D and E and equal radii, draw arcs crossing below the line at F. Join PF; it is perpendicular to the line.

Construction 4: perpendicular at the end of a line

Useful when there is no room to extend the line. At end B: choose any point O above the line, draw a circle with centre O through B, cutting the line again at D. Draw the diameter from D through O to meet the circle at E. BE is perpendicular to the line, because the angle in a semicircle is 90°. An alternative is the 3, 4, 5 method: mark 3 units along the line and 4 units up; if the diagonal measures 5, the angle is a right angle (3² + 4² = 5²). Builders setting out a foundation in Owerri use exactly this with a tape and pegs.

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Practice questions

1. To bisect a straight line you need
  1. compasses and a straight edge
  2. a protractor only
  3. a 45° set square only
  4. dividers only
Show answer

A: compasses and a straight edge
Arcs from both ends above and below give the bisector.

2. Each interior angle of a regular hexagon is
  1. 108°
  2. 135°
  3. 60°
  4. 120°
Show answer

D: 120°
(6 − 2) × 180 ÷ 6 = 120°.

3. Each interior angle of a regular pentagon is
  1. 72°
  2. 100°
  3. 108°
  4. 120°
Show answer

C: 108°
(5 − 2) × 180 ÷ 5 = 108°.

4. The side of a regular hexagon inscribed in a circle of radius 40 mm is
  1. 80 mm
  2. 40 mm
  3. 20 mm
  4. 69.3 mm
Show answer

B: 40 mm
The side of an inscribed hexagon equals the radius.

5. The side of a regular pentagon inscribed in a circle of radius 50 mm is about
  1. 58.8 mm
  2. 50 mm
  3. 62.8 mm
  4. 72 mm
Show answer

A: 58.8 mm
2 × 50 × sin 36° ≈ 58.8 mm.

Key words

Bisect
Divide into two equal parts.
Perpendicular
At 90° to a line.
Perpendicular bisector
Line at 90° through the midpoint of a segment.
Intercept theorem
Parallels cut two lines in the same ratio.
Complementary angles
Angles adding to 90°.
Supplementary angles
Angles adding to 180°.
Equilateral
Having all sides equal.
Isosceles
Having two equal sides.
Scalene
Having no equal sides.
Incentre
Meeting point of angle bisectors; centre of incircle.
Circumcentre
Meeting point of side bisectors; centre of circumcircle.
Centroid
Meeting point of medians.
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