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Further Mathematics · Lesson 3

Surds, indices & logarithms (advanced)

WAECNECO

What the syllabus asks

WAEC: Indices (laws, fractional and negative indices, exponential equations), surds (simplification, operations, rationalisation including binomial denominators, equality of surds, square roots of surds), logarithms (laws, change of base, logarithmic and exponential equations, graphs of exponential and logarithmic functions)

NECO: Indices (laws, fractional and negative indices, exponential equations), surds (simplification, operations, rationalisation including binomial denominators, equality of surds, square roots of surds), logarithms (laws, change of base, logarithmic and exponential equations, graphs of exponential and logarithmic functions)

What you will learn

Key points

Start here: The laws of indices revisited

Indices are shorthand for repeated multiplication: 2⁵ = 2 × 2 × 2 × 2 × 2 = 32. Every law follows from counting the factors.

LawReasonExample
aᵐ × aⁿ = aᵐ⁺ⁿm factors then n more3⁴ × 3² = 3⁶
aᵐ ÷ aⁿ = aᵐ⁻ⁿn factors cancel5⁷ ÷ 5³ = 5⁴
(aᵐ)ⁿ = aᵐⁿn groups of m factors(2³)⁴ = 2¹²
a⁰ = 1aⁿ ÷ aⁿ = a⁰ = 17⁰ = 1
a⁻ⁿ = 1/aⁿa⁰ ÷ aⁿ2⁻³ = 1/8
a^(1/n) = ⁿ√a(a^(1/n))ⁿ = a27^(1/3) = 3
a^(m/n) = (ⁿ√a)ᵐroot first, then power8^(2/3) = 2² = 4
(ab)ⁿ = aⁿbⁿ, (a/b)ⁿ = aⁿ/bⁿrearranging factors(2x)³ = 8x³
Worked example 3.1

Evaluate (27/8)^(−2/3).

  1. Negative index: flip the fraction, giving (8/27)^(2/3).
  2. Take the cube root first, because it keeps the numbers small: ∛(8/27) = 2/3.
  3. Square: (2/3)² = 4/9.
4/9
Worked example 3.2

Evaluate 16^(3/4) × 4^(−1/2).

  1. 16^(3/4) = (⁴√16)³ = 2³ = 8.
  2. 4^(−1/2) = 1/√4 = 1/2.
  3. 8 × 1/2 = 4.
4
⚠️ Common mistake: thinking a negative index gives a negative number. 2⁻³ = 1/8, which is positive.
Try it yourself. Evaluate (0.125)^(−1/3).
Show solution
0.125 = 1/8, so (1/8)^(−1/3) = 8^(1/3) = 2.

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Practice questions

1. Evaluate (64)^(−2/3).
Show worked answer
1/(∛64)² = 1/16.
2. Solve 8^(x−1) = 4^(x+1).
Show worked answer
3x − 3 = 2x + 2, x = 5.
3. Simplify 3√8 + √32 − √18.
Show worked answer
6√2 + 4√2 − 3√2 = 7√2.
4. Rationalise (√3 + 1)/(√3 − 1).
Show worked answer
(√3 + 1)²/2 = (4 + 2√3)/2 = 2 + √3.
5. Find √(8 + 2√15).
Show worked answer
x + y = 8, xy = 15: √5 + √3.

Key words

Index (exponent)
The power to which a base is raised, e.g. 3 in 2³.
Base
The number being raised to a power.
Exponential equation
An equation with the unknown in the index, e.g. 2ˣ = 32.
Surd
An irrational root of a rational number, e.g. √2, ∛5.
Like surds
Surds with the same irrational part, e.g. 3√5 and 7√5.
Conjugate
The expression a − √b paired with a + √b; their product is rational.
Rationalise
To remove surds from a denominator.
Logarithm
logₐ N is the power to which a must be raised to give N.
Common logarithm
Logarithm to base 10, written log or lg.
Natural logarithm
Logarithm to base e (≈ 2.718), written ln.
Characteristic
The whole-number part of a common logarithm.
Mantissa
The decimal part of a common logarithm.
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