Momentum, impulse, work–energy & friction (mechanics)
WAECNECO
What the syllabus asks
WAEC: linear momentum and impulse; conservation of linear momentum; direct impact of two bodies, coalescence, recoil; Newton’s law of restitution (introduction); work, energy (kinetic and potential), power; work–energy principle; friction: limiting friction, coefficient of friction, angle of friction, motion on rough horizontal and inclined planes
NECO: linear momentum and impulse; conservation of linear momentum; direct impact of two bodies, coalescence, recoil; Newton’s law of restitution (introduction); work, energy (kinetic and potential), power; work–energy principle; friction: limiting friction, coefficient of friction, angle of friction, motion on rough horizontal and inclined planes
What you will learn
- Calculate momentum and impulse, and use Ft = mv − mu.
- Apply conservation of momentum to collisions, coalescence, explosions and recoil.
- Use Newton’s law of restitution for direct impact of two spheres.
- Calculate work, kinetic energy, potential energy and power.
- Apply the work–energy principle, including loss of energy in collisions.
- Use F ≤ μR to solve problems on rough horizontal and inclined planes.
- Relate the angle of friction to the coefficient of friction.
Key points
- Momentum p = mv (vector), unit kg m/s = N s.
- Impulse Ft = mv − mu; longer contact time means smaller force.
- Conservation: m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂; coalescence uses (m₁ + m₂)v.
- Explosions and recoil: total momentum stays zero.
- Restitution: v₂ − v₁ = e(u₁ − u₂); e = 1 elastic, e = 0 coalesce.
- Work W = Fs cos θ; no work by forces perpendicular to motion.
- KE = ½mv², PE = mgh; net work = ΔKE; mechanical energy conserved without friction.
- Power P = W/t = Fv; at maximum speed, driving force = resistance.
- Friction F ≤ μR; R = mg on level ground, mg cos θ on an incline.
- Angle of friction: tan λ = μ; a block slips when tan θ exceeds μ.
Start here: Linear momentum
A slow lorry and a fast football can both knock you over. A heavy lorry moving slowly is hard to stop; so is a light bullet moving very fast. The quantity that measures this "quantity of motion" is momentum.
Because momentum is a vector, choose a positive direction and give motion the other way a negative sign.
Find the momentum of (a) a 2000 kg car at 15 m/s, (b) a 0.02 kg bullet at 400 m/s, (c) a 0.5 kg ball moving at 6 m/s to the left (take right as positive).
- (a) p = 2000 × 15 = 30,000 kg m/s.
- (b) p = 0.02 × 400 = 8 kg m/s.
- (c) p = 0.5 × (−6) = −3 kg m/s (3 kg m/s to the left).
A 0.4 kg ball moving at 20 m/s hits a wall and rebounds at 15 m/s. Find the change in momentum.
- Take the original direction as positive: u = +20, v = −15.
- Δp = m(v − u) = 0.4(−15 − 20) = 0.4 × (−35) = −14 kg m/s.
- The magnitude is 14 kg m/s, directed away from the wall.
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Practice questions
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Key words
- Momentum
- Mass × velocity; a vector.
- Impulse
- Force × time; equals change in momentum.
- Conservation of momentum
- Total momentum of a system is constant if no external force acts.
- Coalesce
- Two bodies join and move together after impact.
- Recoil
- The backward motion of a gun or body when it fires or throws something forward.
- Coefficient of restitution e
- Speed of separation ÷ speed of approach in a direct impact; 0 ≤ e ≤ 1.
- Work
- Force × distance moved in the direction of the force; unit joule.
- Kinetic energy
- Energy of motion, ½mv².
- Potential energy
- Energy due to position, mgh.
- Power
- Rate of doing work; unit watt (J/s).
- Friction
- A force opposing relative motion between surfaces in contact.
- Limiting friction
- The maximum frictional force, μR, when sliding is about to start.
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